Bug in range sieve when left boundry is 0 #1471
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In case when `L = 0` and `R > 0`, algorithm will say that 0 and 1 are primes. Index initialization improvement
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It's true. That 0 as left boundary does label 0 and 1 as primes I'm suspicious of the changing of bounds. Has your code been tested on problems elsewhere? We probably should write some tests to make sure this works and will work in the future. |
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In case when
L = 0andR > 0, algorithm will return 0 and 1 as primes.